document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=276460>Question 276460</A>: <I><SPAN STYLE=\"word-break: break-all;\"> can someone please breakdown the process of elimination in algerbra???? here is an example the teacher gave me please help me break this down so I can understand how the teacher got this answer 5x+3y =_11 and 7x-2y=19 the teacher says that this is the answer ( 35/31 -172/31) how did he get this? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #201517 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=201517\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5x+3y=-11 multiply by 2<BR>\n" );
document.write( "7x-2y=19 multiply by 3 & add.<BR>\n" );
document.write( "10x+6y=-22<BR>\n" );
document.write( "21x-6y=57<BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( "31x=35<BR>\n" );
document.write( "x=35/31 ans.<BR>\n" );
document.write( "5*35/31+3y=-11<BR>\n" );
document.write( "175/31+3y=-11<BR>\n" );
document.write( "3y=-11-175/31<BR>\n" );
document.write( "3y=(-11*31-175)/35<BR>\n" );
document.write( "3y=(-341-175)/31<BR>\n" );
document.write( "3y=-516/31<BR>\n" );
document.write( "y=(-516/31)/3<BR>\n" );
document.write( "y=-516/31*1/3<BR>\n" );
document.write( "y=-516/93<BR>\n" );
document.write( "y=-172/31 ans.<BR>\n" );
document.write( "  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );