document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=276098>Question 276098</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An arithmetic sequence has initial term 6 and common difference 624. A geometric sequence has initial term 2 and common ratio 3. Determine an n so the nth term of the arithmetic sequence is that same as the nth term of the geometric sequence.\r<BR>\n" );
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document.write( "I'm not sure how this works, and the only hint I was given was that initial term = a0.  Any help would be so great, thanks for your time. (: </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #201371 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=201371\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6 + 624(n - 1) = 2[3^(n - 1)]\r<BR>\n" );
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document.write( "624n - 618 = (2/3) 3^n\r<BR>\n" );
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document.write( "936n - 927 = 3^n\r<BR>\n" );
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document.write( "you can find n by substituting values\r<BR>\n" );
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document.write( "HINT: between 6 and 10 </SPAN>\n" );
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