document.write( "Question 276167: what is the area of the rectangle whose length is 5 more than twice its width and its perimeter is 70 meters? \n" ); document.write( "
Algebra.Com's Answer #201355 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! L=2W+5 \n" ); document.write( "2L+2W=70 \n" ); document.write( "2(2W+5)+2W=70 \n" ); document.write( "4W+10+2W=70 \n" ); document.write( "6W=70-10 \n" ); document.write( "6W=60 \n" ); document.write( "W=60/6 \n" ); document.write( "W=10 ANS. FOR THE WIDTH. \n" ); document.write( "L=2*10+5 \n" ); document.write( "L=20+5=25 ANS FOR THE LENGTH. \n" ); document.write( "PROOF: \n" ); document.write( "2*25+2*10=70 \n" ); document.write( "50+20=70 \n" ); document.write( "70=70 \n" ); document.write( " |