document.write( "Question 276167: what is the area of the rectangle whose length is 5 more than twice its width and its perimeter is 70 meters? \n" ); document.write( "
Algebra.Com's Answer #201355 by checkley77(12844)\"\" \"About 
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L=2W+5
\n" ); document.write( "2L+2W=70
\n" ); document.write( "2(2W+5)+2W=70
\n" ); document.write( "4W+10+2W=70
\n" ); document.write( "6W=70-10
\n" ); document.write( "6W=60
\n" ); document.write( "W=60/6
\n" ); document.write( "W=10 ANS. FOR THE WIDTH.
\n" ); document.write( "L=2*10+5
\n" ); document.write( "L=20+5=25 ANS FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "2*25+2*10=70
\n" ); document.write( "50+20=70
\n" ); document.write( "70=70
\n" ); document.write( "
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