document.write( "Question 276204: The length of a rectangle is 6 cm less than twice its width. Find the dimensions of the rectangle if its area is 108 cm.
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Algebra.Com's Answer #201346 by checkley77(12844)\"\" \"About 
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LW=108
\n" ); document.write( "L=2W-6
\n" ); document.write( "(2W-6)W=108
\n" ); document.write( "2W^2-6W=108
\n" ); document.write( "2W^2-6W-108=0
\n" ); document.write( "2(W^2-3W-54)=0
\n" ); document.write( "2(W-9)(W+6)=0
\n" ); document.write( "W-9=0
\n" ); document.write( "W=9 ANS
\n" ); document.write( "L=2*9-6
\n" ); document.write( "L=18-6
\n" ); document.write( "L=12 ANS.
\n" ); document.write( "PROOF:
\n" ); document.write( "9*12=108
\n" ); document.write( "108=108
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