document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=276211>Question 276211</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 1 less than a second number. Twice the second number is 4 less than 3 times the first. Find the two numbers.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #201345 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=201345\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=y-1<BR>\n" );
document.write( "2y=3x-4<BR>\n" );
document.write( "Repalce x in the second equation by (y-1) & solve for y<BR>\n" );
document.write( "2y=3(y-1)-4<BR>\n" );
document.write( "2y=3y-3-4<BR>\n" );
document.write( "2y-3y=-7<BR>\n" );
document.write( "-1y=-7<BR>\n" );
document.write( "y=-7/-1<BR>\n" );
document.write( "y=7 ans.<BR>\n" );
document.write( "x=7-1<BR>\n" );
document.write( "x=6 ans.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "2*7=3*6-4<BR>\n" );
document.write( "14=18-4<BR>\n" );
document.write( "14=14 </SPAN>\n" );
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