document.write( "Question 276055: A farmer spends $4,000 to obtain 100 head of livestock.Prices are: calves – $120 each; lambs – $50 each; piglets – $25 each. If he purchased at least one animal of each type and fewer than 10 calves,how many lambs did he buy?\r
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document.write( "a 44 b 46 c 48 d 50 e None of the above \n" );
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Algebra.Com's Answer #201325 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A farmer spends $4,000 to obtain 100 head of livestock.Prices are: calves – $120 each; lambs – $50 each; piglets – $25 each. \n" ); document.write( "If he purchased at least one animal of each type and fewer than 10 calves,how many lambs did he buy? \n" ); document.write( "; \n" ); document.write( "Total animal equation: \n" ); document.write( "C + L + P = 100 \n" ); document.write( ": \n" ); document.write( "Total cost equation \n" ); document.write( "120C + 50L + 25P = 4000 \n" ); document.write( "Simplify, divide by 5 \n" ); document.write( "24C + 10L + 5P = 800 \n" ); document.write( ": \n" ); document.write( "Multiply the 1st equation by 5 subtract from the above, get rid of the pigs! \n" ); document.write( "24C + 10L + 5P = 800 \n" ); document.write( "5C + 5L + 5P = 500 \n" ); document.write( "-----------------------Subtraction, eliminates p \n" ); document.write( "19C + 5L = 300 \n" ); document.write( "5L = 300 - 19C \n" ); document.write( "L = \n" ); document.write( "L = 60 - \n" ); document.write( ": \n" ); document.write( "We know L has to be an integer, therefore C has to be a multiple of 5 \n" ); document.write( "they tell his their are fewer than 10 Calves so obviously C = 5 \n" ); document.write( "L = 60 - \n" ); document.write( "L = 60 - 19 \n" ); document.write( "L = 41 lambs \n" ); document.write( ": \n" ); document.write( "Find the pigs \n" ); document.write( "100 - 5 - 41 = 54 pigs \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution by finding the total cost \n" ); document.write( "120(5) + 41(50) + 25(54) = \n" ); document.write( "600 + 2050 + 1350 = 4000 \n" ); document.write( " \n" ); document.write( " |