document.write( "Question 276177: How do I solve this word problem:
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document.write( "Two consecutive positive odd numbers have the property that their product plus the square of their difference equals 147. Find the larger of these two numbers. \n" );
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Algebra.Com's Answer #201319 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Two consecutive positive odd numbers \n" ); document.write( "x, (x+2) \n" ); document.write( ": \n" ); document.write( "have the property that their product plus the square of their difference equals 147. \n" ); document.write( "x(x+2) + ((x+2) - x)^2 = 147; we know the difference is 2, right? \n" ); document.write( ": \n" ); document.write( "x^2 + 2x + 2^2 = 147 \n" ); document.write( ": \n" ); document.write( "x^2 + 2x + 4 - 147 = 0 \n" ); document.write( ": \n" ); document.write( "x^2 + 2x - 143 = 0 \n" ); document.write( "Factors to: \n" ); document.write( "(x+13)(x-11) = 0 \n" ); document.write( "The positive solution \n" ); document.write( "x = 11, \n" ); document.write( "then \n" ); document.write( "the larger number = 13 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution in the statement: \n" ); document.write( "\"their product plus the square of their difference equals 147.\" \n" ); document.write( "(11 * 13) + (13-11)^2 = 147 \n" ); document.write( "143 + 2^2 = 147\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |