document.write( "Question 276188: Three consecutive even integers are such that the square of the first plus the square of the third is 136. Find the three integers \n" ); document.write( "
Algebra.Com's Answer #201318 by richwmiller(17219) You can put this solution on YOUR website! n^2+(n+4)^2=136 \n" ); document.write( "n^2+n^2+8n+16=136 \n" ); document.write( "2*(n^2+4n+8)=136 \n" ); document.write( "n^2+4n+8=68\r \n" ); document.write( "\n" ); document.write( "n^2+4n-60=0 \n" ); document.write( "(n+10)*(n-6)=0 \n" ); document.write( "n=6 n=-10 \n" ); document.write( "(6,8,10) and (-10,-8,-6) \n" ); document.write( "6^2+10^2=136\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |