document.write( "Question 33723This question is from textbook ratios and fractions
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document.write( ": Please ! help me about this three word problems. I ca not work out.\r
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document.write( " (1) The denominator of a fraction is three more than the numerator. If the numerator is doubled and the denominator is increased by nine, the resulting fraction is equal to ½. What is the original fraction? \r
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document.write( " From yours poor student
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Algebra.Com's Answer #20131 by mukhopadhyay(490) ![]() You can put this solution on YOUR website! Let the numerator be x \n" ); document.write( "The denominator = x+3 \n" ); document.write( "The fraction is now x/(x+3); \n" ); document.write( "Numerator doubled and the denominator is increased by nine makes the fraction: \n" ); document.write( "2x/(x+9) = 1/2 \n" ); document.write( "=> 4x = (x+9) \n" ); document.write( "=> x = 3 \n" ); document.write( "The original fraction is 3/6 = 1/2 \n" ); document.write( " |