document.write( "Question 275998: 5x-3y=15;(5,2) \n" ); document.write( "
Algebra.Com's Answer #201206 by mathjames(8)\"\" \"About 
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5x-3y=15;(5,2)
\n" ); document.write( "first get the value of y
\n" ); document.write( "5{5}-3y=15
\n" ); document.write( "25-3y=15
\n" ); document.write( "-3y=15-25
\n" ); document.write( "-3y=-10
\n" ); document.write( "-3y/-3=-10/-3
\n" ); document.write( "y=10/3\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "5x-3{2}=15
\n" ); document.write( "5x-6=15
\n" ); document.write( "5x=15+6
\n" ); document.write( "5x=21
\n" ); document.write( "5x/5=21/5
\n" ); document.write( "x=21/5
\n" ); document.write( "
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