document.write( "Question 275998: 5x-3y=15;(5,2) \n" ); document.write( "
Algebra.Com's Answer #201206 by mathjames(8)![]() ![]() You can put this solution on YOUR website! 5x-3y=15;(5,2) \n" ); document.write( "first get the value of y \n" ); document.write( "5{5}-3y=15 \n" ); document.write( "25-3y=15 \n" ); document.write( "-3y=15-25 \n" ); document.write( "-3y=-10 \n" ); document.write( "-3y/-3=-10/-3 \n" ); document.write( "y=10/3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5x-3{2}=15 \n" ); document.write( "5x-6=15 \n" ); document.write( "5x=15+6 \n" ); document.write( "5x=21 \n" ); document.write( "5x/5=21/5 \n" ); document.write( "x=21/5 \n" ); document.write( " |