document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=275997>Question 275997</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The second angle of a triangle is 4 times as large as the first. The third angle is 80° more than the sum of the other two angles. Find the measure of the second angle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #201203 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=201203\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The second angle of a triangle is 4 times as large as the first. The third angle is 80° more than the sum of the other two angles. Find the measure of the second angle. \r<BR>\n" );
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document.write( "let one angle be x\r<BR>\n" );
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document.write( "the second angle will be 4x\r<BR>\n" );
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document.write( "The third angle will be 80 more than (x+4x)\r<BR>\n" );
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document.write( "= x+4x+80\r<BR>\n" );
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document.write( "The sum of the angles of the triangle = 180 deg\r<BR>\n" );
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document.write( "x+4x+x+4x+80=180\r<BR>\n" );
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document.write( "10x=180-80<BR>\n" );
document.write( "10x=100<BR>\n" );
document.write( "x=10 first angle\r<BR>\n" );
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document.write( "Second angle is 40\r<BR>\n" );
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document.write( "Third angle is 130 deg. <BR>\n" );
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