document.write( "Question 275984: a cyclist travels 30mi in 3 hours going against the wind and 80mi in 5 hours with wind. What is the rate of the cyclist in still air and what is the rate of the wind? \n" ); document.write( "
Algebra.Com's Answer #201202 by mananth(16946)\"\" \"About 
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cyclist travels 30mi in 3 hours going against the wind and 80mi in 5 hours with wind. What is the rate of the cyclist in still air and what is the rate of the wind?\r
\n" ); document.write( "\n" ); document.write( "let speed of wind be x
\n" ); document.write( "let cycle rate in still air be y\r
\n" ); document.write( "\n" ); document.write( "Distance / rate = time\r
\n" ); document.write( "\n" ); document.write( "30 /y-x = 3
\n" ); document.write( "or y-x=10\r
\n" ); document.write( "\n" ); document.write( "AND
\n" ); document.write( "80 / x+y= 5
\n" ); document.write( "or
\n" ); document.write( "x+y = 80/5
\n" ); document.write( "x+y= 16\r
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\n" ); document.write( "\n" ); document.write( "y-x=10
\n" ); document.write( "x+y=16\r
\n" ); document.write( "\n" ); document.write( "therefore 2y= 26
\n" ); document.write( "y=13 mph\r
\n" ); document.write( "\n" ); document.write( "x=3 mph\r
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