document.write( "Question 275915: The length of a rectangle is 2 cm more than three times the width. Find the dimensions of this rectangle if the area is 21 cm^2.\r
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document.write( "I found the answer by trial and error (9 & 2 1/3) but I need to know how to actually figure it out and show work. Is there another way besides just plugging in numbers? Thank you! \n" );
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Algebra.Com's Answer #201184 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The length of a rectangle is 2 cm more than three times the width. \n" ); document.write( " Find the dimensions of this rectangle if the area is 21 cm^2. \n" ); document.write( ": \n" ); document.write( "There is, and it's pretty easy \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement \n" ); document.write( "\"The length of a rectangle is 2 cm more than three times the width.\" \n" ); document.write( "L = 3W + 2 \n" ); document.write( "and \n" ); document.write( "\" the area is 21 cm^2. \" \n" ); document.write( "L * W = 21 \n" ); document.write( ": \n" ); document.write( "Replace L with (3W+2) from the 1st statement \n" ); document.write( "(3W + 2) * W = 21 \n" ); document.write( "3W^2 + 2W - 21 = 0 \n" ); document.write( "A quadratic equation we can factor \n" ); document.write( "(3W - 7)(W + 3) = 0 \n" ); document.write( "The positive solution \n" ); document.write( "3W = 7 \n" ); document.write( "W = \n" ); document.write( "W = 2 \n" ); document.write( ": \n" ); document.write( "Find the length using L = 3W + 2 \n" ); document.write( "L = 3( \n" ); document.write( "L = 7 + 2 \n" ); document.write( "L = 9 \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check solutions by finding the area \n" ); document.write( "9 * \n" ); document.write( " \n" ); document.write( " |