document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=275872>Question 275872</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the circumference of a circle is 4(pi)/3, then what is half of its area? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #201161 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=201161\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> C=2(pi)r<BR>\n" );
document.write( "2(pi)r=4(pi)/3 <BR>\n" );
document.write( "r=4(pi)/3 * 1/2(pi)<BR>\n" );
document.write( "=4(pi)/6(pi)<BR>\n" );
document.write( "=2/3<BR>\n" );
document.write( ".<BR>\n" );
document.write( "A/2=(pi)r^2/2<BR>\n" );
document.write( "=(pi)(2/3)^2/2<BR>\n" );
document.write( "=(pi)(4/9) * 1/2<BR>\n" );
document.write( "=(2(pi))/9<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );