document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=275845>Question 275845</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm having problems coming up with an equation to this mixture problem, perhaps you can help (you guys are awsome!)\r<BR>\n" );
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document.write( "Two different teas are mixed to make a blend that will be sold at a fair.  Black tea is sells for $2.20 per pound, and orange pekoe tea sells for $3.00 per pound.  How much of each shoould be used to obtain a 4 pound of a blend selling for $2.50?  \r<BR>\n" );
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document.write( "I have tried 2.5 + 3 + = 4(2.5) + 2x, but having trouble.  <BR>\n" );
document.write( "Thanks for your help\r<BR>\n" );
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document.write( "Alex<BR>\n" );
document.write( "avargas91702@hotmail.com </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #201145 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=201145\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two different teas are mixed to make a blend that will be sold at a fair.<BR>\n" );
document.write( " Black tea is sells for $2.20 per pound, and orange pekoe tea sells for $3.00 per pound.<BR>\n" );
document.write( " How much of each should be used to obtain a 4 pound of a blend selling for $2.50? <BR>\n" );
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document.write( "Let x = amt of $3 tea<BR>\n" );
document.write( "it gives the resulting amt as 4 lb, therefore<BR>\n" );
document.write( "(4-x) = amt $2.20 tea<BR>\n" );
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document.write( "A typical mixture equation:<BR>\n" );
document.write( "3x + 2.2(4-x) = 2.5(4)<BR>\n" );
document.write( "3x + 8.8 - 2.2x = 10<BR>\n" );
document.write( "3x - 2.2x = 10 - 8.8<BR>\n" );
document.write( ".8x = 1.2<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1.2%2F%28.8%29 ALIGN=MIDDLE  ALT=\"1.2%2F%28.8%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = 1.5 lb of $3 tea required<BR>\n" );
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document.write( "I'll let you find the amt of 2.20 tea </SPAN>\n" );
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