document.write( "Question 275763: a log 78 feet long is to be cut into three pieces of varying lengths. The longest piece is to be four times the length of the shortest piece and the middle-sized piece is to be 6 feet less than twice the length of the shortest piece. How long is the shortes piece? \n" ); document.write( "
Algebra.Com's Answer #201113 by checkley77(12844)\"\" \"About 
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Longest=4s
\n" ); document.write( "Middle=2s-6
\n" ); document.write( "l+m+s=78
\n" ); document.write( "4s+2s-6+s=78
\n" ); document.write( "7s=78+6
\n" ); document.write( "7s=84
\n" ); document.write( "s=84/7
\n" ); document.write( "s=12 ft. for the shortest piece.
\n" ); document.write( "l=4*12=48 ft. for the longest piece.
\n" ); document.write( "m=2*12-6=24-6=18 ft. for the middle piece.
\n" ); document.write( "Proof:
\n" ); document.write( "12+48+18=78
\n" ); document.write( "78=78
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