document.write( "Question 275795: Beth wants to make 11.6 fl. oz. of a 45% acid solution by mixing together a 22% acid solution and a 80% acid solution. How much of each solution must she use? \n" ); document.write( "
Algebra.Com's Answer #201112 by mananth(16946)\"\" \"About 
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Beth wants to make 11.6 fl. oz. of a 45% acid solution by mixing together a 22% acid solution and a 80% acid solution. How much of each solution must she use?\r
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\n" ); document.write( "\n" ); document.write( "Let the 22% solution required be x\r
\n" ); document.write( "\n" ); document.write( "The total required = 11.6 oz\r
\n" ); document.write( "\n" ); document.write( "22%------------------80%-----------45% strength\r
\n" ); document.write( "\n" ); document.write( "x--------------------11.6-x---------11.6 Quantity\r
\n" ); document.write( "\n" ); document.write( "0.22x+0.8(11-x) = 0.45*11.6\r
\n" ); document.write( "\n" ); document.write( "0.22x+8.8-0.8x=5.22\r
\n" ); document.write( "\n" ); document.write( "-0.58x==-3.58\r
\n" ); document.write( "\n" ); document.write( "x=-3.58/-0.58
\n" ); document.write( " = 6.17 oz of 22% acid\r
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\n" ); document.write( "\n" ); document.write( "11.6-6.17 = 5.43 oz\r
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