document.write( "Question 33541This question is from textbook Addison-Wesley Geometry
\n" ); document.write( ": May you please help me with this question??:
\n" ); document.write( "If the volume of a right cone is 72p(72 PI, can't put the sign on, srry), find the surface area if its height and radius are equal.\r
\n" ); document.write( "\n" ); document.write( "Thank you.
\n" ); document.write( "

Algebra.Com's Answer #20108 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Let's first find the radius of the right circular cone from the given information.
\n" ); document.write( "The volume of a right circular cone is given by:
\n" ); document.write( "\"V+=+%281%2F3%29%28pi%29r%5E2h\" = \"72%28pi%29\" but since r = h we can rewrite this and simplify it.
\n" ); document.write( "\"%281%2F3%29%28pi%29r%5E3+=+72%28pi%29\" Divide both sides by\"pi\" and multiply both sides by 3.
\n" ); document.write( "\"r%5E3+=+216\" Take the cube-root of both sides.
\n" ); document.write( "\"r+=+6\"
\n" ); document.write( "So the radius, r = 6\r
\n" ); document.write( "\n" ); document.write( "The surface (lateral) area of a right circular cone is given by:
\n" ); document.write( "\"S+=+%28pi%29r%2Asqrt%28r%5E2%2Bh%5E2%29\" but since r = h, we can rewrite this and simplify it.
\n" ); document.write( "\"S+=+%28pi%29r%2Asqrt%28r%5E2%2Br%5E2%29\"
\n" ); document.write( "\"S+=+%28pi%29r%2Asqrt%282r%5E2%29\"
\n" ); document.write( "\"S+=+%28pi%29r%5E2%2Asqrt%282%29\" Now substitute r = 6.
\n" ); document.write( "\"S+=+%28pi%296%5E2%2Asqrt%282%29\"
\n" ); document.write( "\"S+=+36%28pi%29%2Asqrt%282%29\" This is the surface area of the cone.
\n" ); document.write( "
\n" );