document.write( "Question 275711: How do i find the area of a 45°-45°-90° triangle with a 4-cm hypotenuse \n" ); document.write( "
Algebra.Com's Answer #201060 by stanbon(75887)\"\" \"About 
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How do i find the area of a 45°-45°-90° triangle with a 4-cm hypotenuse
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\n" ); document.write( "45-45l means the two legs are equal in length; let their length be \"x\":
\n" ); document.write( "Equation:
\n" ); document.write( "x^2 + x^2 = 4^2
\n" ); document.write( "2x^2 = 16
\n" ); document.write( "x^2 = 8
\n" ); document.write( "x = 2sqrt(2)
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\n" ); document.write( "Area = (1/2)(leg)(leg)
\n" ); document.write( "Area = (1/2)(8)
\n" ); document.write( "Area = 4 sqrt cm
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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