document.write( "Question 275711: How do i find the area of a 45°-45°-90° triangle with a 4-cm hypotenuse \n" ); document.write( "
Algebra.Com's Answer #201060 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! How do i find the area of a 45°-45°-90° triangle with a 4-cm hypotenuse \n" ); document.write( "----- \n" ); document.write( "45-45l means the two legs are equal in length; let their length be \"x\": \n" ); document.write( "Equation: \n" ); document.write( "x^2 + x^2 = 4^2 \n" ); document.write( "2x^2 = 16 \n" ); document.write( "x^2 = 8 \n" ); document.write( "x = 2sqrt(2) \n" ); document.write( "------------ \n" ); document.write( "Area = (1/2)(leg)(leg) \n" ); document.write( "Area = (1/2)(8) \n" ); document.write( "Area = 4 sqrt cm \n" ); document.write( "====================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |