document.write( "Question 275685: The width of a poster is four fifths the length. It takes 36 ft. of metal framing to frame the poster. Find the dimensions of the poster. \n" ); document.write( "
Algebra.Com's Answer #201054 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! W=4/5L \n" ); document.write( "2L+2W=36 \n" ); document.write( "2L+2(4/5L)=36 \n" ); document.write( "2L+8L/5=36 \n" ); document.write( "(5*2L+8L)/5=36 \n" ); document.write( "(10L+8L)/5=36 \n" ); document.write( "18L/5=36 CROSS MULTIPLY \n" ); document.write( "18L=180 \n" ); document.write( "L=180/18 \n" ); document.write( "L=10 ANS. FOR THE LENGTH. \n" ); document.write( "W=4/5*10 \n" ); document.write( "W=40/5=8 ANS. FOR THE WIDTH. \n" ); document.write( "PROOF: \n" ); document.write( "2*10+2*8=36 \n" ); document.write( "20+16=36 \n" ); document.write( "36=36 \n" ); document.write( " \n" ); document.write( " |