document.write( "Question 275685: The width of a poster is four fifths the length. It takes 36 ft. of metal framing to frame the poster. Find the dimensions of the poster. \n" ); document.write( "
Algebra.Com's Answer #201054 by checkley77(12844)\"\" \"About 
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W=4/5L
\n" ); document.write( "2L+2W=36
\n" ); document.write( "2L+2(4/5L)=36
\n" ); document.write( "2L+8L/5=36
\n" ); document.write( "(5*2L+8L)/5=36
\n" ); document.write( "(10L+8L)/5=36
\n" ); document.write( "18L/5=36 CROSS MULTIPLY
\n" ); document.write( "18L=180
\n" ); document.write( "L=180/18
\n" ); document.write( "L=10 ANS. FOR THE LENGTH.
\n" ); document.write( "W=4/5*10
\n" ); document.write( "W=40/5=8 ANS. FOR THE WIDTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "2*10+2*8=36
\n" ); document.write( "20+16=36
\n" ); document.write( "36=36
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