document.write( "Question 33685: I don't know how to solve x(to the fourth) minus (five x squared) plus four.
\n" ); document.write( "In school we did something called a diamond formula or something with a diamond and it makes everything easier but i don't understand. Can you explain to me how to solve this by the diamond formula. Thank you.
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Algebra.Com's Answer #20100 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Well, I don't believe I've heard of the \"diamond formula\" for solving 4th-degree polynomials.
\n" ); document.write( "But try this method:
\n" ); document.write( "Solve:
\n" ); document.write( "\"x%5E4+-5x%5E2%2B4+=+0\" Rewrite this as:
\n" ); document.write( "\"%28x%5E2%29%5E2+-+5%28x%5E2%29+%2B+4+=+0\" Temporarily set \"x%5E2+=+y\"
\n" ); document.write( "\"y%5E2+-+5y+%2B+4+=+0\" Solve this quadratic equation in y by factoring.
\n" ); document.write( "\"%28y+-+1%29%28y+-+4%29+=+0\" Apply the zero products principle.
\n" ); document.write( "\"y+-+1+=+0\" and/or \"y+-+4+=+0\"
\n" ); document.write( "If \"y+-+1+=+0\" then \"y+=+1\"
\n" ); document.write( "If \"y+-+4+=+0\" then \"y+=+4\"\r
\n" ); document.write( "\n" ); document.write( "But, \"y+=+x%5E2\", so:
\n" ); document.write( "\"x%5E2+=+1\" Take the square root of both sides.
\n" ); document.write( "\"x+=+1\" or \"x+=+-1\" and:
\n" ); document.write( "\"x%5E2+=+4\" Take the square root of both sides.
\n" ); document.write( "\"x+=+2\" or \"x+=+-2\"\r
\n" ); document.write( "\n" ); document.write( "The roots are:
\n" ); document.write( "x = 1
\n" ); document.write( "x = -1
\n" ); document.write( "x = 2
\n" ); document.write( "x = -2\r
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