document.write( "Question 275564: A car travels from one town to another at a speed of 32 mph. If it had gone 4 mph faster, it could have made the trip in 1/2 hr less time. How far apart are the towns?\r
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document.write( "So far I have 32t = 36t + 18
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document.write( "-32t + 32t = 36t - 32t + 18 - 18
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document.write( "-18 = 4t
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document.write( "-18/4t = 4t/4
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document.write( "-4 1/2 = t\r
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document.write( "d = 32t
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document.write( "d = 32(-4.5)
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document.write( "d = -144
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document.write( "Is this right?
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Algebra.Com's Answer #200987 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The distance cannot be negative so I guess your work is questionable. \n" ); document.write( "---------------- \n" ); document.write( "A car travels from one town to another at a speed of 32 mph. If it had gone 4 mph faster, it could have made the trip in 1/2 hr less time. How far apart are the towns? \n" ); document.write( "--- \n" ); document.write( "Early DATA: \n" ); document.write( "rate = 32 mph ; distance = x miles; time = d/r = x/32 hrs \n" ); document.write( "-------------------- \n" ); document.write( "New DATA: \n" ); document.write( "rate = 36 mph ; distance = x miles ; time = d/r = x/36 hrs \n" ); document.write( "------------------------- \n" ); document.write( "Equation: \n" ); document.write( "old time - new time = 1/2 hr \n" ); document.write( "(x/32) - (x/36) = 1/2 \n" ); document.write( "--- \n" ); document.write( "Simplify the left side to get: \n" ); document.write( "(36x-32x)/32*36 = 1/2 \n" ); document.write( "4x = (32*36)/2 \n" ); document.write( "x = (9*16) \n" ); document.write( "x = 144 miles (distance apart) \n" ); document.write( "===== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |