document.write( "Question 275564: A car travels from one town to another at a speed of 32 mph. If it had gone 4 mph faster, it could have made the trip in 1/2 hr less time. How far apart are the towns?\r
\n" ); document.write( "\n" ); document.write( "So far I have 32t = 36t + 18
\n" ); document.write( "-32t + 32t = 36t - 32t + 18 - 18
\n" ); document.write( "-18 = 4t
\n" ); document.write( "-18/4t = 4t/4
\n" ); document.write( "-4 1/2 = t\r
\n" ); document.write( "\n" ); document.write( "d = 32t
\n" ); document.write( "d = 32(-4.5)
\n" ); document.write( "d = -144
\n" ); document.write( "Is this right?
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Algebra.Com's Answer #200987 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The distance cannot be negative so I guess your work is questionable.
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\n" ); document.write( "A car travels from one town to another at a speed of 32 mph. If it had gone 4 mph faster, it could have made the trip in 1/2 hr less time. How far apart are the towns?
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\n" ); document.write( "Early DATA:
\n" ); document.write( "rate = 32 mph ; distance = x miles; time = d/r = x/32 hrs
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\n" ); document.write( "New DATA:
\n" ); document.write( "rate = 36 mph ; distance = x miles ; time = d/r = x/36 hrs
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\n" ); document.write( "Equation:
\n" ); document.write( "old time - new time = 1/2 hr
\n" ); document.write( "(x/32) - (x/36) = 1/2
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\n" ); document.write( "Simplify the left side to get:
\n" ); document.write( "(36x-32x)/32*36 = 1/2
\n" ); document.write( "4x = (32*36)/2
\n" ); document.write( "x = (9*16)
\n" ); document.write( "x = 144 miles (distance apart)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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