document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=275482>Question 275482</A>: <I><SPAN STYLE=\"word-break: break-all;\"> -9 + 4x < 2x - 3<BR>\n" );
document.write( "Solve using the addition and multiplication principles.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #200980 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=200980\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -9 + 4x < 2x - 3<BR>\n" );
document.write( "-9+3<2X-4X<BR>\n" );
document.write( "-6<-2X<BR>\n" );
document.write( "-6/-2>X [NOTE THE SIGN CHANGES WHEN DIVIDING BY A NEGATIVE VALUE]<BR>\n" );
document.write( "3>X ANS.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "LET X=2.9<BR>\n" );
document.write( "-9+4*2.9<2*2.9-3<BR>\n" );
document.write( "-9+11.6<5.8-3<BR>\n" );
document.write( "2.6<2.8<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );