document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=275532>Question 275532</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the length of a base of a  traingle with a height of 864 and a area of 1871 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #200962 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=200962\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> AREA=BH/2<BR>\n" );
document.write( "1,871=B*864/2<BR>\n" );
document.write( "1,871=864B/2<BR>\n" );
document.write( "864B=1,871*2<BR>\n" );
document.write( "864B=3,742<BR>\n" );
document.write( "B=3,742/864<BR>\n" );
document.write( "B=4.331 ANS. FOR THE BASE MEASUREMENT.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "1,871=4.331*864/2<BR>\n" );
document.write( "1,871=3,742//2<BR>\n" );
document.write( "1,871=1,871 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );