document.write( "Question 275504: if you take a certain two-digit number and reverse its digits to get another two-digit number, then add these two numbers together, their sum is 132. what is the original number? \n" ); document.write( "

Algebra.Com's Answer #200938 by mananth(16946) $\"\"$ $\"About$

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if you take a certain two-digit number and reverse its digits to get another two-digit number, then add these two numbers together, their sum is 132. what is the original number?\r
\n" ); document.write( "\n" ); document.write( "Let the digit in the units place be y
\n" ); document.write( "& in the tens place be x\r
\n" ); document.write( "\n" ); document.write( "So the number will be 10x+y\r
\n" ); document.write( "\n" ); document.write( "On reversing the digits
\n" ); document.write( "the number becomes 10y+x\r
\n" ); document.write( "\n" ); document.write( "The sum of the two = 132\r
\n" ); document.write( "\n" ); document.write( "10x+y + 10y+x= 132\r
\n" ); document.write( "\n" ); document.write( "11x+11y=132\r
\n" ); document.write( "\n" ); document.write( "x+y=12\r
\n" ); document.write( "\n" ); document.write( "To satisfy this equation only three pairs are possible
\n" ); document.write( "48, 57, 66\r
\n" ); document.write( "\n" ); document.write( "All the three numbers wheen reversed and added give you 132\r
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