document.write( "Question 275440: The sum of two integers are 10. Three times one integer is 3 less than 8 times the other integer. Find the numbers.\r
\n" ); document.write( "\n" ); document.write( "I have tried 3x + 8(10 - x) - 3=10, also 3(10 - x)+ 8x - 3, I've started out on x+y=10, so if one integer is x, the other has to be (10 - x), like x + (10 - x)=10, but no answer. It seems like an easy one, can you help?\r
\n" ); document.write( "\n" ); document.write( "Thank you,\r
\n" ); document.write( "\n" ); document.write( "Alex Vargas
\n" ); document.write( "avargas91702@hotmail.com \n" ); document.write( "
Algebra.Com's Answer #200922 by mananth(16946)\"\" \"About 
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The sum of two integers are 10. Three times one integer is 3 less than 8 times the other integer. Find the numbers.\r
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\n" ); document.write( "\n" ); document.write( "Let the integer be x\r
\n" ); document.write( "\n" ); document.write( "Three times = 3x\r
\n" ); document.write( "\n" ); document.write( "other integer = 8*(10-x)\r
\n" ); document.write( "\n" ); document.write( "The difference is = 3\r
\n" ); document.write( "\n" ); document.write( "8*(10-x)-3x= 3\r
\n" ); document.write( "\n" ); document.write( "80-8x-3x=3\r
\n" ); document.write( "\n" ); document.write( "-11x=-77\r
\n" ); document.write( "\n" ); document.write( "x= -77/-11\r
\n" ); document.write( "\n" ); document.write( "x=7\r
\n" ); document.write( "\n" ); document.write( "the other number is 24\r
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