document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=275471>Question 275471</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The first of two numbers is one more than twice the second. The sum of twice the first number and three times the second number is 51. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #200918 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=200918\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The first of two numbers is one more than twice the second. The sum of twice the first number and three times the second number is 51. Find the numbers.\r<BR>\n" );
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document.write( "Let the second number be x\r<BR>\n" );
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document.write( "twice the second = 2x\r<BR>\n" );
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document.write( "1 more means 2x+1  This is the second number\r<BR>\n" );
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document.write( "twice the first number =2x\r<BR>\n" );
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document.write( "three times the second will be 3*(2x+1)\r<BR>\n" );
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document.write( "2x+3*(2x+1) = 51\r<BR>\n" );
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document.write( "2x+6x+3=51\r<BR>\n" );
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document.write( "8x=51-3\r<BR>\n" );
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document.write( "8x=48\r<BR>\n" );
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document.write( "x=6  first number\r<BR>\n" );
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document.write( "2* x= 2*6 = 12 the second number\r<BR>\n" );
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document.write( " </SPAN>\n" );
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