document.write( "Question 275448: Two cities are 405 miles apart. A car leaves one of the cities traveling toward the second city at 60mph. At the same time, a bus leaves the second city bound for the first city at 75mph. How long will it take them to meet? \n" ); document.write( "
Algebra.Com's Answer #200910 by mananth(16946)\"\" \"About 
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Two cities are 405 miles apart. A car leaves one of the cities traveling toward the second city at 60mph. At the same time, a bus leaves the second city bound for the first city at 75mph. How long will it take them to meet?\r
\n" ); document.write( "\n" ); document.write( "Let the distance traveled by the car when they meet be x. Speed of car is 60 mph\r
\n" ); document.write( "\n" ); document.write( "The bus would have traveled 405 -x miles . speed of bus is 75mph\r
\n" ); document.write( "\n" ); document.write( "Time taken by car when they meet will be x/60\r
\n" ); document.write( "\n" ); document.write( "Time taken by bus when they meet will be 405-x / 75\r
\n" ); document.write( "\n" ); document.write( "So x/60 = 405-x / 75\r
\n" ); document.write( "\n" ); document.write( "75x = 60 ( 405-x)\r
\n" ); document.write( "\n" ); document.write( "75x= 24300 -60x\r
\n" ); document.write( "\n" ); document.write( "75x+60x=24300\r
\n" ); document.write( "\n" ); document.write( "x= 24300 / 135
\n" ); document.write( "x= 180 \r
\n" ); document.write( "\n" ); document.write( "180 /60 =3 hours \r
\n" ); document.write( "\n" ); document.write( "They meet after 3 hours.\r
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