document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=275405>Question 275405</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the least common multiple:<BR>\n" );
document.write( "(a) 6 and 8\r<BR>\n" );
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document.write( "(b) 15 and 36 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #200871 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=200871\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the least common multiple:<BR>\n" );
document.write( "(a) 6 and 8<BR>\n" );
document.write( "6 = 2*3<BR>\n" );
document.write( "8 = 2^3<BR>\n" );
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document.write( "lcm has each prime factor in its highest power:<BR>\n" );
document.write( "lcm = 3*2^3 = 24<BR>\n" );
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document.write( "(b) 15 and 36<BR>\n" );
document.write( "15 = 3*5<BR>\n" );
document.write( "36 = 2^2*3^2<BR>\n" );
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document.write( "lcm = 2^2*3^2*5 = 180<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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