document.write( "Question 275393: A sales person purchased an automobile that was advertised as averaging 25mi/gal in the city and 40 mi/gal on the highway. A recent sales trip that covered 1800 miles required 51 gallons of gasoline. Assuming that the advertised mileage estimates were correct, how many miles were driven in the city?\r
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document.write( "I'm really stumped on how to approach this problems because it seems the answer could possibly have more than one correct answer if there is not a number of highway miles given, or the answer would have a variable in it. \n" );
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Algebra.Com's Answer #200868 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A sales person purchased an automobile that was advertised as averaging 25mi/gal in the city and 40 mi/gal on the highway. \n" ); document.write( "----------------------------- \n" ); document.write( "A recent sales trip that covered 1800 miles required 51 gallons of gasoline.\r \n" ); document.write( "\n" ); document.write( "Assuming that the advertised mileage estimates were correct, how many miles were driven in the city? \n" ); document.write( "==== \n" ); document.write( "Let x be the city miles. \n" ); document.write( "Then 1800-x are the highway miles. \n" ); document.write( "--- \n" ); document.write( "distance/miles per gallon = gallons \n" ); document.write( "----- \n" ); document.write( "Equation: \n" ); document.write( "gallons + gallons = 51 gallons \n" ); document.write( "x/25 + (1800-x)/40 = 51 gallons \n" ); document.write( "--- \n" ); document.write( "Multiply thru by 25*40 to get: \n" ); document.write( "40x + 25*1800 - 25x = 51*25*40 \n" ); document.write( "15x = 6000 \n" ); document.write( "x = 400 (miles of city driving) \n" ); document.write( "======================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |