document.write( "Question 275147: how do i do elimination\r
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document.write( "a+c=2200
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document.write( "4a+1.5c-5050
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Algebra.Com's Answer #200859 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! how do i do elimination \n" ); document.write( "Assume the last - is supposed to be an = \n" ); document.write( ": \n" ); document.write( "a + c = 2200 \n" ); document.write( "4a + 1.5c = 5050 \n" ); document.write( ": \n" ); document.write( "Multiply the 1st equation by 4, subtract the 2nd equation \n" ); document.write( "4a + 4c = 8800 \n" ); document.write( "4a+1.5c = 5050 \n" ); document.write( "--------------------subtraction eliminates a, find c \n" ); document.write( "2.5c = 3750 \n" ); document.write( "c = \n" ); document.write( "c = 1500 \n" ); document.write( ": \n" ); document.write( "Find a, substitute 1500 for c in the 1st equation \n" ); document.write( "a + 1500 = 2200 \n" ); document.write( "a = 2200 - 1500 \n" ); document.write( "a = 700 \n" ); document.write( ": \n" ); document.write( "a = 700, c = 1500 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution in the 2nd equation \n" ); document.write( "4a + 1.5c = 5050 \n" ); document.write( "4(700) + 1.5(1500) = \n" ); document.write( "2800 + 2250 = 5050; confirms our solutions \n" ); document.write( " |