document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=275242>Question 275242</A>: <I><SPAN STYLE=\"word-break: break-all;\"> tom is 4 times as old as todd. in 5 years toms age will be 1 year less than 3 times as old as todd. how old is tom? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #200849 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=200849\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> tom is 4 times as old as todd. in 5 years toms age will be 1 year less than 3 times as old as todd. how old is tom?\r<BR>\n" );
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document.write( "Let x be Todd's age and y Tom's. Then we have:\r<BR>\n" );
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document.write( "1.) y = 4*x \r<BR>\n" );
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document.write( "In 5 years their ages will be x+5 and y+5 so we have:\r<BR>\n" );
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document.write( "2.) y+5 = 3*(x+5)-1\r<BR>\n" );
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document.write( "We can substitute 4x for y in 2.) and solve for x:\r<BR>\n" );
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document.write( "4x+5 = 3*(x+5)-1\r<BR>\n" );
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document.write( "Once you have x you can calculate y = 4*x. </SPAN>\n" );
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