document.write( "Question 33660This question is from textbook College Alegbra
\n" ); document.write( ": 1)An open-top box is to be constructed from a 6 by 8 foot rectangular cardboard by cutting out equal squares at each corner and the folding up the flaps. Let x denote the length of each side of the square to be cut out.
\n" ); document.write( "a)Find the function V that represents the volume of the box in terms of x.
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\n" ); document.write( "\n" ); document.write( "b)Graph this function.
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\n" ); document.write( "\n" ); document.write( "c)Using the graph, what is the value of x that will produce the maximum volume?
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\n" ); document.write( "\n" ); document.write( "2)The volume of a cylinder (think about the volume of a can) is given by V = pr2h where r is the radius of the cylinder and h is the height of the cylinder. Suppose the volume of the can is 100 cubic centimeters.
\n" ); document.write( "a)Write h as a function of r.
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\n" ); document.write( "\n" ); document.write( "b)What is the measurement of the height if the radius of the cylinder is 2 centimeters?
\n" ); document.write( "Answer \r
\n" ); document.write( "\n" ); document.write( "Show work in this space \r
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\n" ); document.write( "\n" ); document.write( "c)Graph this function.
\n" ); document.write( "Show graph here
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Algebra.Com's Answer #20084 by venugopalramana(3286)\"\" \"About 
You can put this solution on YOUR website!
WHEN WE CUT X LONG PIECES ON ALL 4 SIDES THE CARD BOARD WILL GET REDUCED BY
\n" ); document.write( "X+X=2X...ALONG LENGTH AND...X+X=2X.....ALONG WIDTH
\n" ); document.write( "SO OPEN BOX LENGTH = 8-2X AND WIDTH = 6-2X..AND HEIGHT =X ...SO VOLUME V IS GIVEN BY LEMGTH*WIDTH*HEIGHT
\n" ); document.write( "V=(8-2X)(6-2X)X...DOMAIN OF V IS GIVEN BY THE FACT THAT LENGTH OR WIDTH CAN NOT BE NEGATIVE...CRITICAL VALUE BEING WIDTH WE GET ....
\n" ); document.write( " 8-2X>0...AND 6-2X>0...SO X <3
\n" ); document.write( "RANGE.....MAXIMUM VALUE........
\n" ); document.write( "V=X(8-2X)(6-2X)=X{48-16X-12X+4X^2)=4X^3-28X^2+48X...IF YOU KNOW CALCULUS
\n" ); document.write( "DV/DX=12X^2-56X+48=0..OR...3X^2-14X+12=0....
\n" ); document.write( "X=(14+SQRT.(52))/6...OR......(7+SQRT.(13))/3...OR....(7-SQRT.13)/3
\n" ); document.write( "X=3.54..OR...1.13.
\n" ); document.write( "D2V/DX2=6X-14=- VE AT X=1.13...SO MAXIMUM VOLUME IS OBTAINED AT X=1.13'
\n" ); document.write( "YOU CAN SEE IT BY PLOTTING THE GRAPH.
\n" ); document.write( "\"graph%28+500%2C+500%2C+-2%2C+3%2C+-2%2C+200%2C+4%2A%28x%5E3%29-28%2A%28x%5E2%29%2B48%2Ax%29\"
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\n" ); document.write( "The volume of a cylinder (think about the volume of a can) is given by V = pr2h where r is the radius of the cylinder and h is the height of the cylinder. Suppose the volume of the can is 100 cubic centimeters.
\n" ); document.write( "a)Write h as a function of r.
\n" ); document.write( "Answer
\n" ); document.write( "100=PI*R^2*H
\n" ); document.write( "H=100/(PI*R^2)
\n" ); document.write( "b)What is the measurement of the height if the radius of the cylinder is 2 centimeters?
\n" ); document.write( "Answer
\n" ); document.write( "H=100/(PI*2^2)=25/PI=7.96 CM.\r
\n" ); document.write( "\n" ); document.write( "Show work in this space\r
\n" ); document.write( "\n" ); document.write( "c)Graph this function.
\n" ); document.write( "Show graph here
\n" ); document.write( "\"graph%28+500%2C+500%2C+-2%2C+10%2C+-2%2C+10%2C+100%2F%283.14%2A%28x%5E2%29%29%29\"
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