document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=275281>Question 275281</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this equation..  3|-8x-9|=117 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #200793 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=200793\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3|-8x-9|=117\r<BR>\n" );
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document.write( "We have two cases.  First when -8x-9 >= 0 the equation above becomes:\r<BR>\n" );
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document.write( "3*(-8x-9) = 117<BR>\n" );
document.write( "-24x - 27 = 117<BR>\n" );
document.write( "-24x = 90<BR>\n" );
document.write( "x = -90/24 = -15/4 when\r<BR>\n" );
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document.write( "-8x - 9 >= 0<BR>\n" );
document.write( "8x <= -9<BR>\n" );
document.write( "x <= -9/8 \r<BR>\n" );
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document.write( "In the second case when -8x-9 < 0 the original equation becomes:\r<BR>\n" );
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document.write( "3*-(-8x-9) = 117<BR>\n" );
document.write( "3*(8x+9) = 117<BR>\n" );
document.write( "24x + 27 = 117<BR>\n" );
document.write( "24x = 90<BR>\n" );
document.write( "x = 90/24 = 15/4 when\r<BR>\n" );
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document.write( "-8x-9 < 0<BR>\n" );
document.write( "-8x < 9<BR>\n" );
document.write( "x > 9/-8 <BR>\n" );
document.write( "x > -9/8 \r<BR>\n" );
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document.write( "The solution set is {15/4, -15/4}  </SPAN>\n" );
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