document.write( "Question 275259: Can someone explain how to find the zeroes of the following problem?\r
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Algebra.Com's Answer #200776 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
The zeros are the x values which make the equation \"2x%5E2-x%2B4=0\" true.\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E2-x%2B4=0\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "Notice that the quadratic \"2x%5E2-x%2B4\" is in the form of \"Ax%5E2%2BBx%2BC\" where \"A=2\", \"B=-1\", and \"C=4\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for \"x\":\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%28-1%29+%2B-+sqrt%28+%28-1%29%5E2-4%282%29%284%29+%29%29%2F%282%282%29%29\" Plug in \"A=2\", \"B=-1\", and \"C=4\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B-+sqrt%28+%28-1%29%5E2-4%282%29%284%29+%29%29%2F%282%282%29%29\" Negate \"-1\" to get \"1\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B-+sqrt%28+1-4%282%29%284%29+%29%29%2F%282%282%29%29\" Square \"-1\" to get \"1\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B-+sqrt%28+1-32+%29%29%2F%282%282%29%29\" Multiply \"4%282%29%284%29\" to get \"32\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B-+sqrt%28+-31+%29%29%2F%282%282%29%29\" Subtract \"32\" from \"1\" to get \"-31\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B-+sqrt%28+-31+%29%29%2F%284%29\" Multiply \"2\" and \"2\" to get \"4\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B-+i%2Asqrt%2831%29%29%2F%284%29\" Simplify the square root (note: If you need help with simplifying square roots, check out this solver) \r
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\n" ); document.write( "\n" ); document.write( "Recall that 'i' is the imaginary number and \"i=sqrt%28-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281%2Bi%2Asqrt%2831%29%29%2F%284%29\" or \"x+=+%281-i%2Asqrt%2831%29%29%2F%284%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "So the zeros are \"x+=+%281%2Bi%2Asqrt%2831%29%29%2F%284%29\" or \"x+=+%281-i%2Asqrt%2831%29%29%2F%284%29\" \r
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\n" ); document.write( "\n" ); document.write( "Note: if you've never seen imaginary numbers before, then the answer is simply \"no solutions\"
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