document.write( "Question 275262: Can someone help with the following problem with finding the zeroes?\r
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Algebra.Com's Answer #200764 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
The zeros are the x values that make \"f%28x%29=0\". In other words, they are the x values that satisfy the equation \"5x%5E2+-+2x+-+1=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"5x%5E2-2x-1=0\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "Notice that the quadratic \"5x%5E2-2x-1\" is in the form of \"Ax%5E2%2BBx%2BC\" where \"A=5\", \"B=-2\", and \"C=-1\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for \"x\":\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%28-2%29+%2B-+sqrt%28+%28-2%29%5E2-4%285%29%28-1%29+%29%29%2F%282%285%29%29\" Plug in \"A=5\", \"B=-2\", and \"C=-1\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B-+sqrt%28+%28-2%29%5E2-4%285%29%28-1%29+%29%29%2F%282%285%29%29\" Negate \"-2\" to get \"2\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B-+sqrt%28+4-4%285%29%28-1%29+%29%29%2F%282%285%29%29\" Square \"-2\" to get \"4\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B-+sqrt%28+4--20+%29%29%2F%282%285%29%29\" Multiply \"4%285%29%28-1%29\" to get \"-20\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B-+sqrt%28+4%2B20+%29%29%2F%282%285%29%29\" Rewrite \"sqrt%284--20%29\" as \"sqrt%284%2B20%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B-+sqrt%28+24+%29%29%2F%282%285%29%29\" Add \"4\" to \"20\" to get \"24\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B-+sqrt%28+24+%29%29%2F%2810%29\" Multiply \"2\" and \"5\" to get \"10\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B-+2%2Asqrt%286%29%29%2F%2810%29\" Simplify the square root (note: If you need help with simplifying square roots, check out this solver) \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%282%2B2%2Asqrt%286%29%29%2F%2810%29\" or \"x+=+%282-2%2Asqrt%286%29%29%2F%2810%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281%2Bsqrt%286%29%29%2F%285%29\" or \"x+=+%281-sqrt%286%29%29%2F%285%29\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x+=+%281%2Bsqrt%286%29%29%2F%285%29\" or \"x+=+%281-sqrt%286%29%29%2F%285%29\"
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