document.write( "Question 275234: Please help me solve my equation. Airplan travels 3490km against the wind in 5 hours and 3940 km with the wind in the same amount of time. what is the rate of the plane in still air and what is the wind rate? \n" ); document.write( "
Algebra.Com's Answer #200761 by checkley77(12844) ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "3,490=R*5 \n" ); document.write( "R=3,490/5 \n" ); document.write( "R=698 KMH IS THE RATE AGAINST THE WIND. \n" ); document.write( "3,940=5*5 \n" ); document.write( "R=3,940/5 \n" ); document.write( "R=788 KMH IS THE RATE OF THE PLANE WITH THE WIND. \n" ); document.write( "(788-698)/2 \n" ); document.write( "90/2=45 KMH IS THE RATE OF THE WIND. \n" ); document.write( "698+45=743 KPH IS THE RATE OF THE PLANE IN STILL AIR. \n" ); document.write( "788-45=743 DITTO. \n" ); document.write( " |