document.write( "Question 275234: Please help me solve my equation. Airplan travels 3490km against the wind in 5 hours and 3940 km with the wind in the same amount of time. what is the rate of the plane in still air and what is the wind rate? \n" ); document.write( "
Algebra.Com's Answer #200761 by checkley77(12844)\"\" \"About 
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D=RT
\n" ); document.write( "3,490=R*5
\n" ); document.write( "R=3,490/5
\n" ); document.write( "R=698 KMH IS THE RATE AGAINST THE WIND.
\n" ); document.write( "3,940=5*5
\n" ); document.write( "R=3,940/5
\n" ); document.write( "R=788 KMH IS THE RATE OF THE PLANE WITH THE WIND.
\n" ); document.write( "(788-698)/2
\n" ); document.write( "90/2=45 KMH IS THE RATE OF THE WIND.
\n" ); document.write( "698+45=743 KPH IS THE RATE OF THE PLANE IN STILL AIR.
\n" ); document.write( "788-45=743 DITTO.
\n" ); document.write( "
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