document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=33666>Question 33666</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the geometric sequence of numbers 1, 1/2, 1/4, 1/8,…to find the following:<BR>\n" );
document.write( "a)What is r, the ratio between 2 consecutive terms? \r<BR>\n" );
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document.write( "b)Using the formula for the sum of the first n terms of a geometric series, what is the sum of the first 10 terms? Round your answer to 4 decimals.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20075 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20075\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a) r = 1/2<BR>\n" );
document.write( "b) S(n) = a(1-r^n)/(1-r)<BR>\n" );
document.write( "   S(10)= 1(1-(1/2)^10)/(1/2)<BR>\n" );
document.write( "   S(10)= (0.999......)/(1/2)=1.9980<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "        <BR>\n" );
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