document.write( "Question 275013: how to write two thirds of a number increased by six is three less than the number \n" ); document.write( "
Algebra.Com's Answer #200670 by Edwin McCravy(20054)\"\" \"About 
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document.write( "two thirds of a number increased by six is three less than the number.\r\n" );
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document.write( "two thirds of a number increased by six is three less than the number.\r\n" );
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document.write( "Replace \"a number\" and \"the number\" by \"x\r\n" );
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document.write( "two thirds of x increased by six is three less than \"red%28x%29\".\r\n" );
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document.write( "two thirds of x increased by six is three less than x.\r\n" );
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document.write( "Replace \"two thirds of x\" by \"\"red%282%2F3%29\"\"red%28x%29\"\"\r\n" );
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document.write( "\"red%282%2F3%29\"\"red%28x%29\" increased by six is three less than x.\r\n" );
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document.write( "\"red%282%2F3%29\"\"red%28x%29\" increased by six is three less than x.\r\n" );
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document.write( "Replace \"\"red%282%2F3%29\"\"red%28x%29\"  increased by six\" by \"\"red%282%2F3%29\"\"red%28x%29\"\"red%28%22%2B%22%29\"\"red%286%29\"\"\r\n" );
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document.write( "\"\"red%282%2F3%29\"\"red%28x%29\"\"red%28%22%2B%22%29\"\"red%286%29\"\" is three less than x.\r\n" );
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document.write( "\"\"2%2F3\"\"x\"\"%22%2B%22\"\"6\"\" is three less than x.\r\n" );
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document.write( "Replace the word \"is\" by an equal sign \"red%28%22=%22%29\"\r\n" );
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document.write( "\"2%2F3\"\"x\"\"%22%2B%22\"\"6\"\"red%28%22%22=%22%22%29\" three less than x.\r\n" );
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document.write( "\"2%2F3\"\"x\"\"%22%2B%22\"\"6\"\"%22%22=%22%22\" three less than x\r\n" );
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document.write( "The last part is tricky because the English is backwards from the algebra:\r\n" );
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document.write( "So first replace \"three less than x\" by \"x decreased by three\".  You see,\r\n" );
document.write( "it's x that we are decreasing, not \"three\". The \"three\" tells us how much\r\n" );
document.write( "we are decreasing x.  So any time you see the words \"less than\" in a word\r\n" );
document.write( "problem, be very careful to decide what is being decreased and what we are\r\n" );
document.write( "decreasing it by, for it is very important that you do not get these reversed.\r\n" );
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document.write( "\"2%2F3\"\"x\"\"%22%2B%22\"\"6\"\"%22%22=%22%22\"x decreased by three.\r\n" );
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document.write( "Now replace \"x decreased by three\" by \"red%28x%29\"\"red%28%22%22-%22%22%29\"\"red%283%29\"\r\n" );
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document.write( "\"2%2F3\"\"x\"\"%22%2B%22\"\"6\"\"%22%22=%22%22\"\"red%28x%29\"\"red%28%22%22-%22%22%29\"\"red%283%29\"\r\n" );
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document.write( "Can you solve that? If not post again asking how.\r\n" );
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document.write( "Answer \"x=27\"\r\n" );
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document.write( "Edwin
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