document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=274977>Question 274977</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Diameter of a circle. If the diameter of a circle is 1.3*10^12 meters, then what is its radius?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #200650 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=200650\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Diameter of a circle. If the diameter of a circle is 1.3*10^12 meters, then what is its radius? <BR>\n" );
document.write( "The radius is 1/2 the diameter.<BR>\n" );
document.write( "d = 1.3E-12<BR>\n" );
document.write( "r = 0.65E-12 = 6.5E-13<BR>\n" );
document.write( "Or 6.5*10^13 if you prefer the inconvenience<BR>\n" );
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document.write( "I would call it 0.65 picometers, or 650 attometers, myself<BR>\n" );
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