document.write( "Question 274940: A car travels from one town to another at a speed of 32 mph. If it had gone 4 mph faster, it could have made the trip in 1/2 hr less time. How far apart are the towns?. \n" ); document.write( "
Algebra.Com's Answer #200647 by dabanfield(803)\"\" \"About 
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A car travels from one town to another at a speed of 32 mph. If it had gone 4 mph faster, it could have made the trip in 1/2 hr less time. How far apart are the towns?.\r
\n" ); document.write( "\n" ); document.write( "If the distance between towns is d and the time needed to travel at 32 mph is t then we have:\r
\n" ); document.write( "\n" ); document.write( " d = 32*t or
\n" ); document.write( "1.) t = d/32\r
\n" ); document.write( "\n" ); document.write( "At the faster speed (32+4=36) it takes .5 hours less to travel the same distance so we have:\r
\n" ); document.write( "\n" ); document.write( " d = 36*(t - 1/2) or
\n" ); document.write( "2.) d = 36*t - 18\r
\n" ); document.write( "\n" ); document.write( "From 1.) we know that t = d/32 so we can substitute d/32 for t in equation 2.) which gives us:\r
\n" ); document.write( "\n" ); document.write( "d = 36*(d/32) - 18
\n" ); document.write( "d = (36/32)*d - 18
\n" ); document.write( "d = (9/8)*d - 18
\n" ); document.write( "(9/8)*d - d = 18
\n" ); document.write( "d/8 = 18
\n" ); document.write( "d = 18*8 = 144
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