document.write( "Question 274955: If an arrow is shot vertically upward with an initial velocity of 49 m/s, the height in metres reached in t seconds can be found the equation h=49t-4.9tsquared. Find the maximum height reached by the arrow. \n" ); document.write( "
Algebra.Com's Answer #200635 by Alan3354(69443)\"\" \"About 
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If an arrow is shot vertically upward with an initial velocity of 49 m/s, the height in metres reached in t seconds can be found the equation h=49t-4.9tsquared. Find the maximum height reached by the arrow.
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\n" ); document.write( "\"h%28t%29+=+49t+-+4.9t%5E2\"
\n" ); document.write( "When there's no 3rd term, the easiest way to do these is to find the time at apogee, which is 1/2 the total time.
\n" ); document.write( "Find the times when h= 0
\n" ); document.write( "\"-4.9t%5E2+%2B+49t+=+0\"
\n" ); document.write( "t = 0 (at the start)
\n" ); document.write( "t = 10 (at impact)
\n" ); document.write( "The midpoint is the apogee, at t = 5 seconds
\n" ); document.write( "h(5) = 49*5 - 4.9*25
\n" ); document.write( "h max = 122.5 meters
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\n" ); document.write( "If the 3rd term is not zero(0), then find the vertex at t = -b/2a
\n" ); document.write( "t = -49/-9.8 = 5 seconds
\n" ); document.write( "same result
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