document.write( "Question 274951: A, B and C are whole and positive numbers.
\n" ); document.write( "A+B+C=38 and A*B*C=630. What are the numbers? \r
\n" ); document.write( "\n" ); document.write( "How do I find that out with three variables and only two equations?\r
\n" ); document.write( "\n" ); document.write( "Thanks so much!
\n" ); document.write( "Guðrún \n" ); document.write( "
Algebra.Com's Answer #200625 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Because we're only looking for positive integer solutions, this set of solutions will be finite even though we're missing a third equation. To find these solutions, simply list all of the factors of 630 and see which set of 3 factors add up to 38. For example, 630=2*5*63 which means that 2+5+63=70.\r
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\n" ); document.write( "\n" ); document.write( "It turns out that there are only 6 sets of solutions and they are\r
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\n" ); document.write( "\n" ); document.write( "A = 2, B = 15, C = 21
\n" ); document.write( "A = 2, B = 21, C = 15
\n" ); document.write( "A = 15, B = 2, C = 21
\n" ); document.write( "A = 15, B = 21, C = 2
\n" ); document.write( "A = 21, B = 2, C = 15
\n" ); document.write( "A = 21, B = 15, C = 2\r
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\n" ); document.write( "\n" ); document.write( "For example, when A = 2, B = 15, C = 21, then 2*15*21=630 and 2+15+21=38\r
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\n" ); document.write( "\n" ); document.write( "Basically, there are 3 unique numbers here (they're just being rearranged) and the numbers are 2, 15, and 21. \n" ); document.write( "
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