document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=33158>Question 33158</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A circular swimming pool with a diameter of 30 ft and a horizontal bottom contains 22,000 gal of water.  What is the depth of the water in the pool? (one cubic foot contains approx. 7.5 gal of water) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20061 by </B><A HREF=/tutors/aboutme.mpl?userid=kietra><B>kietra(57)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kietra><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20061\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The basics of the problem are that you are finding the volume of water in a pool which is a cyllinder shape.  The formula for volume is V= (r^2)(h)(pi). Notice the formula requires the radius but we are given diamter so cut the diameter in half to get radius- half of 30 is 15.\r<BR>\n" );
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document.write( "Substituting what we know and simplifying:<BR>\n" );
document.write( "22,000 gal = (15ft^2)(H)(pi)<BR>\n" );
document.write( "(22,000gal)/(255 ft^2)(pi) = (H) H is in ft.<BR>\n" );
document.write( "31.1236gal/sq.ft = H ft<BR>\n" );
document.write( "Using 1cubic foot per 7.5 gal of water, we divide 31.1236 gal/7.5 giving you H=4.1498  </SPAN>\n" );
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