document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=274904>Question 274904</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Bob's frog can travel  6 inches per jump, Kim's frog can travel  9 inches, and Jack's frog can travel  13 inches. If the three frogs start off at point 0 inches, how many inches will it be to the next point that all three frogs touch?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #200586 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=200586\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> OK.  We need to find the Least Common Multiple (LCM) of 6, 9 & 13.  To do this we will break each of the numbers down into their prime factors:<BR>\n" );
document.write( "6=3*2<BR>\n" );
document.write( "9=3*3=3^2<BR>\n" );
document.write( "13=1*13 <BR>\n" );
document.write( "Next, we take the highest power that appears for each of the prime numbers and we get:<BR>\n" );
document.write( "2, 3^2&13. Now we multiply these together to get the LCM:<BR>\n" );
document.write( "18*13= 234 inches to the next point that all three frogs touch<BR>\n" );
document.write( "CK <BR>\n" );
document.write( "frog 1 makes 39 jumps to get to 234 inches<BR>\n" );
document.write( "frog 2 makes 26 jumps to get to 234 inches<BR>\n" );
document.write( "frog 3 makes 18 jumps to get to 234 inches\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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