document.write( "Question 274907: Jill is 27.5 km away from Joe. Both begin walking toward each other at the same time. Jill walks at 2.5 km per hour. If they meet in 5 hours, how fast is Joe walking?
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document.write( "x + y = 27.5
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document.write( "x(2.5)-y=5 (??) \n" );
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Algebra.Com's Answer #200569 by edjones(8007) You can put this solution on YOUR website! st=d \n" ); document.write( "Let j=Joe's speed & t=5 \n" ); document.write( "5(2.5+j)=27.5 \n" ); document.write( "12.5+5j=27.5 \n" ); document.write( "5j=15 \n" ); document.write( "j=3 km/h \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |