document.write( "Question 274874: In a pair of supplementary angles, one angle measures 24 degrees more than twice the other angle. Find the measure of each angle. I tried it like this: 2x+24+x not sure how to solve this one. Thanks, Meg \n" ); document.write( "
Algebra.Com's Answer #200548 by ankor@dixie-net.com(22740)\"\" \"About 
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In a pair of supplementary angles, one angle measures 24 degrees more than twice the other angle. Find the measure of each angle.
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\n" ); document.write( "Let x = \"other angle\"
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\n" ); document.write( "The pair is supplementary, so they add up to 180, therefore
\n" ); document.write( "(180-x) = one angle
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\n" ); document.write( "It says,\"one angle measures 24 degrees more than twice the other angle.\"
\n" ); document.write( "therefore we can write it like this and solve for x:
\n" ); document.write( "(180-x) = 2x + 24
\n" ); document.write( "180 - 24 = 2x + x
\n" ); document.write( "156 = 3x
\n" ); document.write( "x = \"156%2F3\"
\n" ); document.write( "x = 52 degrees is the other angle
\n" ); document.write( "then
\n" ); document.write( "180 - 52 = 128 degrees is \"one angle\"
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\n" ); document.write( "See if this is true in the statement:
\n" ); document.write( "\"one angle measures 24 degrees more than twice the other angle.
\n" ); document.write( "128 = 2(52) + 24
\n" ); document.write( "128 = 104 + 24; confirms our solutions here \n" ); document.write( "
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