document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=274809>Question 274809</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the radius of a circular region were decreased by 20 percent, the area of the circular region would decrease by what percent?\r<BR>\n" );
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document.write( "A  16%  b 20%  c  36%  d  44%<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #200534 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=200534\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the radius of a circular region were decreased by 20 percent, the area of the circular region would decrease by what percent? \r<BR>\n" );
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document.write( "If R is the original radius then the area of the circle is pi*R^2\r<BR>\n" );
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document.write( "If we decrease the radius by 20% the new radius is .8*R so the new area is:<BR>\n" );
document.write( "pi*(.8*R)^2 = pi*(.64*R^2).\r<BR>\n" );
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document.write( "Compute the percent of the new to the old:\r<BR>\n" );
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document.write( "(pi*.64R^2)/(pi*R^2) = .64\r<BR>\n" );
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document.write( "The decrease then is 100 - 64 = 36%  </SPAN>\n" );
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