document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=274752>Question 274752</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the slope of the line 5x +2y =1.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #200487 by </B><A HREF=/tutors/aboutme.mpl?userid=anantha><B>anantha(86)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=anantha><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=200487\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> equation of the line=<BR>\n" );
document.write( "5x+2y=1<BR>\n" );
document.write( "the  equation  is of the form ax+by+c=0 then<BR>\n" );
document.write( " the slope of the line= -(x coefficient)/(y coefficient)<BR>\n" );
document.write( "step1:1st we convert given line in to ax+by+c=0 for this we subtract 1 on both sides<BR>\n" );
document.write( "5x+2y-1=1-1<BR>\n" );
document.write( "5x+2y-1=0<BR>\n" );
document.write( "now the equation is of the form ax+by+c=0<BR>\n" );
document.write( "slope= -(x coefficient)/(y coefficient)<BR>\n" );
document.write( "here x coefficient=5,y coefficient=2<BR>\n" );
document.write( "slope= -(5)/2 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );