document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=274705>Question 274705</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many gallons of a 50% antifreeze soltuion must be mixed with 70 gallons of 15% antifreeze to get a mixture that is 40% antifreeze </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #200473 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=200473\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .50x+.15*70=.40(70+x)<BR>\n" );
document.write( ".50x+10.5=28+.40x<BR>\n" );
document.write( ".50x-.40x=28-10.5<BR>\n" );
document.write( ".10x=17.5<BR>\n" );
document.write( "x=17.5/.10<BR>\n" );
document.write( "x=175 gal of 50% antifreeze is used.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( ".50*175+.15*70=.40(70+175)<BR>\n" );
document.write( "87.5+10.5=.40*245<BR>\n" );
document.write( "98=98<BR>\n" );
document.write( " </SPAN>\n" );
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